3000 bacteria with a growth constnt 3.8 are present at begining of experment howmanyhr wil there be 15000?

Bacterial growth is given by


dN/dt = kN


where dN is the change in number of bacteria over time (dt) which is equal to a constant (k, a first-order rate constant in reciprocal time units) multiplied by the number of cells at a given time, t





So,


dN/dt = kN


(15000-3000)/dt = 3.8 * 3000


12000/dt = 11400


12000/11400 = dt


1.053 = dt





So, in a little over an hour, you will have 15000 bacteria, assuming the units of the growth constant are per hour.